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julikinss

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H

hocvuima

$A=(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2010}).2.3.4.5...2010$
$A=(\dfrac{2011}{1.2010}+\dfrac{2011}{2.2009}+...+\dfrac{2011}{1005.1006}).2.3.4...2010$
$A=(\dfrac{1}{1.2010}+\dfrac{1}{2.2009}+\dfrac{1}{3.2008}+...+\dfrac{1}{1005.1006}).2.3.4.5...2010.2011\vdots 2011$
Vậy $A\vdots 2011$
 
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