[Toán] căn bậc 2 khó

H

hien_vuthithanh

$\sqrt{13-4\sqrt{3}}-\dfrac{1}{2-\sqrt{3}}$
=$\sqrt{(2\sqrt{3}-1)^2}-\dfrac{1}{2-\sqrt{3}}$
=$2\sqrt{3}-1-\dfrac{1}{2-\sqrt{3}}$
=$\dfrac{5\sqrt{3}-8}{2-\sqrt{3}}$
=$2\sqrt{3}-1$
 
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