[tex]\frac{a+b}{\sqrt{a(3a+b)}+\sqrt{b(3b+a)}}=\frac{2(a+b)}{\sqrt{4a(3a+b)}+\sqrt{4b(3b+a)}}\geq \frac{2(a+b)}{\frac{7a+b}{2}+\frac{7b+a}{2}}=\frac{2(a+b)}{4(a+b)}= \frac{1}{2}[/tex]
dấu bằng xảy ra khi a=b
1.
[tex]3x+2y+\frac{6}{x}+\frac{8}{y}=\frac{3}{2}x+\frac{6}{x}+\frac{y}{2}+\frac{8}{y}+\frac{3}{2}(x+y)\\\geq 6+4+\frac{3}{2}.6=19[/tex]
Dấu = xảy ra khi x=2,y=4