Rg đc:
$M=\dfrac{\sqrt{x-1}}{x}+\dfrac{\sqrt{y-2}}{y}+\dfrac{\sqrt{z-3}}{z}$
Có: $x-1+1 \ge 2\sqrt{x-1}$
\Rightarrow $\dfrac{\sqrt{x-1}}{x} \le \dfrac{1}{2}$
TT có: $\dfrac{\sqrt{y-2}}{y} \le \dfrac{1}{2\sqrt{2}}$
$\dfrac{\sqrt{z-3}}{z} \le \dfrac{1}{2\sqrt{3}}$
\Rightarrow $M \le....$
Dấu "=" xảy ra \Leftrightarrow $x=2;y=4;z=6$