[Toán 9] Tính $\dfrac{x^5+1}{x^5}$

K

kool_boy_98

Anh chị tham khảo:

$$\frac{x^2 + 1}{x^2} = 7$$

$$\Longleftrightarrow ( \frac{x+1}{x})^2 - 2 =7$$

$$\Longleftrightarrow \frac{x+1}{x}=3$$

$$\Longleftrightarrow (\frac{x+1}{x})^3= 27$$

$$\Longleftrightarrow \frac{x^3+1}{x^3} + 3\frac{x+1}{x} = 27$$

$$\Longleftrightarrow \frac{x^3+1}{x^3} + 9 =27$$

$$\Longleftrightarrow \frac{x^3+1}{x^3} = 18$$

$$\Longleftrightarrow \frac{x^2 + 1}{x^2}.\frac{x^3+1}{x^3} = 126$$

$$\Longleftrightarrow \frac{x^5+1}{x^5}+\frac{x+1}{x}=126$$

$$\Longleftrightarrow \frac{x^5+1}{x^5} = 123$$.
 
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