[Toán 9] Tính $A=\dfrac{1+x+x^2+x^3+....+x^9}{1+y+y^2+y^3+....+y ^9}$

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hockhongngung98

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nguyenbahiep1

[TEX]1 + x +x^2 + ..+x^9 = \frac{x^{10} -1}{x-1} \\ \Rightarrow A = \frac{(x^{10}-1)(y-1)}{(y^{10} -1)(x-1)} = 0,000004129[/TEX]
 
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