[toán 9] tìm x

N

nguyenbahiep1

câu 1

[laTEX]u = \sqrt[3]{14+x} \\ \\ v = \sqrt[3]{14-x} \\ \\ u^3 +v^3 = 28 \Rightarrow (u+v)[(u+v)^2-3uv] = 28 \\ \\ u+v = 4 \Rightarrow 4.( 16 -3uv) = 28 \Rightarrow uv = 3 \\ \\ u^2 -4u+3 = 0 \Rightarrow u = 1 \Rightarrow x = 13 \\ \\ u = 3 \Rightarrow x = -13[/laTEX]
 
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