[Toán 9] Tìm x,y,z

P

pinkylun

L

lp_qt

ta có:
$(x+1)(y+1)=2$

$(y+1)(z+1)=4$


$(x+1)(z+1)=8$

nhân theo vế \Rightarrow $[(x+1)(y+1)(z+1)]^2=64$

\Rightarrow $x+1=...;y+1=...;z+1=...$
 
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