[Toán 9]Tìm Min $A = \dfrac{-3(\sqrt{x} -2 )}{\sqrt{ x}+1}$

V

vy000

Bà i này phải là tìm max bạn ạ

nếu coi $\sqrt x=a \ge 0$ thì:

$A=\dfrac{-3(a-2)}{a+1}$

$=-3+\dfrac 9{a+1} \le 6$

Dấu "=" $\Leftrightarrow a=0$

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