[toán 9] hệ phương trình

E

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+Xét $x=\dfrac{1}{2}$\Rightarrow ktm

+Xét $x$ khác $\dfrac{1}{2}$

PT(1) \Leftrightarrow $y(2x-1)=x+1$

\Rightarrow $y=\dfrac{x+1}{2x-1}$

PT(3) \Leftrightarrow $z(2x-1)=x+2$

\Rightarrow $z=\dfrac{x+2}{2x-1}$

Thay vào PT(2),đc:

$2.\dfrac{x+1}{2x-1}.\dfrac{x+2}{2x-1}=\dfrac{x+2}{2x-1}+\dfrac{x+1}{2x-1}+7$

\Leftrightarrow $2(x+1)(x+2)=(2x-1)(16x-4)$

\Leftrightarrow $15x^2-15x=0$

\Leftrightarrow ...
 
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