[Toán 9]Đường tròn

D

doanhnhanvanhoa

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C

congchuaanhsang

$\hat{AMO}$ max \Leftrightarrow $sin \hat{AMO}$ max

Kẻ OH vuông góc với AM

$sin\hat{AMO}=\dfrac{OH}{OM}$ \leq $\dfrac{OA}{OM}=\dfrac{1}{2}$

\Rightarrow $max \hat{AMO}=30^0$ \Leftrightarrow $AM$ vuông góc với $AO$
 
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