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thangkhoyeucondadai


Bài 1: Tìm nghiêm nguyên của phương trình:
a)(x-1)(y+1)=[TEX]{(x+y)}^{2}[/TEX]
b)[TEX]\frac{xy}{z}+\frac{yz}{x}+\frac{zx}{y}=3[/TEX]
c)[TEX]{x}^{2}-xy+{y}^{2}=3[/TEX]
d)[TEX]{x}^{2}+{y}^{2}-x-y=8[/TEX]
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a)(x-1)(y+1)=[TEX]{(x+y)}^{2}[/TEX]
b)[TEX]\frac{xy}{z}+\frac{yz}{x}+\frac{zx}{y}=3[/TEX]
c)[TEX]{x}^{2}-xy+{y}^{2}=3[/TEX]
d)[TEX]{x}^{2}+{y}^{2}-x-y=8[/TEX]
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