[toán 9] chứng minh đẳng thức

S

soicon_boy_9x

$\dfrac{1}{1+a}+\dfrac{1}{1+b}+\dfrac{1}{1+c}= \dfrac{ x } { x+ax }+\dfrac{y}{y+by}+\dfrac{z}{z+cz}=\dfrac{by+cz}{ax+by+cz}+\dfrac{ax+cz}{ax+by+cz}+\dfrac{ax+by}{ax+by+cz}=2$
 
Top Bottom