M
mamy007


tìm Min cua P=[TEX]\frac{1}{2x+Y+z}+\frac{1}{2y+x+z}+\frac{1}{2z+x+y}[/TEX]
biết [TEX]\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=8[/TEX]
biết [TEX]\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=8[/TEX]
Last edited by a moderator: