[Toán 9] Bất đẳng thức

B

braga

[TEX]\Large \red Note: \ \ \frac{a^2}{b^5}+\frac{a^2}{b^5}+\frac{a^2}{b^5}+ \frac { 1 } {a ^3 }+\frac{1}{a^3}\ge 5\sqrt[5]{\frac{1}{b^{15}}}=\frac{5}{b^3}[/TEX]​
 
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