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kimphuong1032
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Giải pt:
1) $(2x + 3) (\frac{3x + 8}{2 - 7x} + 1) = (x - 5) (\frac{3x + 8}{2 - 7x} + 1)$
2) $\frac{x^2 + 3x + 7}{x^2 + 5x - 6} = \frac{3x + 2}{x + 15}$
1) $(2x + 3) (\frac{3x + 8}{2 - 7x} + 1) = (x - 5) (\frac{3x + 8}{2 - 7x} + 1)$
2) $\frac{x^2 + 3x + 7}{x^2 + 5x - 6} = \frac{3x + 2}{x + 15}$