toán 8

R

ronaldover7

x^7+x^2+1=x^7-x^4+x^4-x+x^2+x+1
=x^4(x^3-1)+x(x^3-1)+x^2+x+1=x^4(x-1)(x^2+x+1)+x(x-1)(x^2+x+1)+(x^2+x+1)
=(x^2+x+1)(x^5-x^4+x^2-x+1)
(cau dau minh ko giai dc sr nhe'!)
bam dung zum minh nhe'!
:)
 
H

huuthuyenrop2

$x^7+x^2+1$
=$x^7-x+x^2+x+1$
=$x(x^3+1)(x^3-1)+(x^2+x+1)$
= $(x^2+x+1)(x^5-x^4+x^2-x+1)$
 
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