Toán 8

T

th1104

$x^6 - x^4 + 2 x^3 + 2x^2 = 0$

\Leftrightarrow $x^2(x^4 - x^2 + 2x + 2 ) = 0$

\Leftrightarrow $x^2[x^2(x-1)(x+1) + 2 (x+1)] = 0$

\Leftrightarrow $x^2 (x+1)(x^3 - x^2 +2) = 0$

\Leftrightarrow $x^2(x+1)(x+1)(x^2 - 2x + 2) = 0 $

Tự làm
 
L

lovelybones311

$x^6-x^4+2x^3+2x^2=0$
$<=>x^2(x^4-x^2+2x+2)=0$
$<=>x^2[x^2(x^2-1)+2(x+1)]=0$
$<=>x^2(x+1)[x^2(x-1)+2]=0$
$<=>x^2(x+1)(x^3-x^2+2)=0$
$<=>x^2(x+1)[(x+1)(x^2-x+1)-(x-1)(x+1)]=0$
$<=>x^2.(x+1)^2.(x^2-x+1-x+1)=0$
$<=>x^2.(x+1)^2.[(x-1)^2+1]=0$
<=> x=0 hay x=-1
 
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