toán 8

T

tk1

[TEX]2^{105}+3^{105}=(2^3)^{35}+(3^3)^{35}=8^{35}+27^{35}[/TEX] chia hết 8+27=35 chia hết cho 7(đpcm)
[TEX]2^{105}+3^{105}=(2^5)^{21}+(3^5)^{21}=32^{21}+243^{21}[/TEX] chia hết cho 32+243=275 chia hết cho 11(đpcm)
[TEX]2^{105}+3^{105}=(2^7)^{15}+(3^7)^{15}=128^{15}+2187^{15}[/TEX] chia hết cho 128+2187=2315 chia hết cho 463(đpcm)

Chú ý latex
 
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