T
thanhvan_da1988


sorry nham de.lai ne:
so sanh
[TEX]\frac{(2^2+1)(3^2+1)(4^2+1)...(100^2+1)}{(2^2-1)(3^2-1)(4^2-1)...(100^2-1)}[/TEX]
va 1,5
so sanh
[TEX]\frac{(2^2+1)(3^2+1)(4^2+1)...(100^2+1)}{(2^2-1)(3^2-1)(4^2-1)...(100^2-1)}[/TEX]
va 1,5