toan 8

L

linh11997

ai lam đc thì giup minh với.thanks nhiều nha
so sánh:
[TEX{(2^3+1)(3^3+1)(4^3+1)...(100^3+1)}][/TEX{(2^3-1)(3^3-1)(4^3-1)...(100^3-1)}]
và 1,5
To lam the nay kg biet co dung kg,nhung cau cu tham khao nhe:
{(2^3+1)(3^3+1)(4^3+1)...(100^3+1)}{(2^3-1)(3^3-1)(4^3-1)...(100^3-1)}
={(2+1)(2^2-2+1)(3+1)(3^2-3+1)...(100+1)(100^2-100+1)}{(2-1)(2^2+2+1)(3-1)(3^2+3+1)...(100-1)(100^2+100+1)}
=2.3.4^2.5^2...99^2.100.101.(2+1)(2.3+1)(3.4+1)...(99.100+1)(2.3+1)(3.4+1)...(100.101+1)>1,5
Dung thi nho thanks nha
 
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