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thang3320100
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
bài 1: giatricua x+y biet $x-y= 4xy = 5$ (x<0)
bai2: gia tri cua x biet $(2x+1)^2-4(x+2)^2=9?$
bai3 giatricua : $x^3+9x^2y+27xy^2+27y^3$ biet $\dfrac{1}{3}x+y+1=0$ ;
bai4 số nguyên tố x thoả mãn $x^2-8x+7=0$ ;
bai5 gtln cua $3+15x-5x^2$ ; gia tri cua $\dfrac{3^(x+y)^2}{3^(x-y)^2}$ biet $xy=\dfrac{1}{2}$ ;
bai6 giatri cua $x^2+y^2$ biet : $x+y=2$ va $x-y = \dfrac{3\sqrt{2}}{2}$.
bai2: gia tri cua x biet $(2x+1)^2-4(x+2)^2=9?$
bai3 giatricua : $x^3+9x^2y+27xy^2+27y^3$ biet $\dfrac{1}{3}x+y+1=0$ ;
bai4 số nguyên tố x thoả mãn $x^2-8x+7=0$ ;
bai5 gtln cua $3+15x-5x^2$ ; gia tri cua $\dfrac{3^(x+y)^2}{3^(x-y)^2}$ biet $xy=\dfrac{1}{2}$ ;
bai6 giatri cua $x^2+y^2$ biet : $x+y=2$ va $x-y = \dfrac{3\sqrt{2}}{2}$.
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