toán 8 về PTDTTNT

N

nguyenbahiep1

áp dụng hằng đẳng thức
[TEX]A^2-B^2 = (A-B)(A+B)[/TEX]


câu 1

[TEX](a^2 + b^2 - 5 )^2 - 4.(ab - 2 )^2 = (a^2 + b^2 - 5 )^2 - (2(ab - 2 ))^2 \\ (a^2+b^2-5-2ab+4)(a^2+b^2-5+2ab-4) = ((a-b)^2-1)((a+b)^2-9) = ( a-b-1)(a-b+1)(a+b-3)(a+b+3)[/TEX]


[TEX](4x^3 - 3x - 18 )^2 - (4x^2 + 3x)^2 = (4x^3-3x-18-4x^2-3x)(4x^3-3x-18+4x^2+3x) \\ (4x^3-4x^2-6x-18)(4x^3+4x^2-18)[/TEX]
 
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