[toán 8]toan hay

K

katanaoa

bai 1 nha:
-p^3+q^3=(p+q)(p^2-pq+q^2)=2 =>p+q=2/(p^2-pq+q^2)
de dang chung minh (p^2-pq+q^2) > 0(ko the ban 0 vi neu bang 0 thi vo nghia)
=>p+q>0(1)
- do (p^2-pq+q^2) lon hon hoac bang 0 => (p+q)nho hon hoac bang (p+q)(p^2-pq+q^2)
=> (p+q)nho hon hoac bang 2 (2)
tu (1) va (2 ) =>dpcm
 
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