[Toán 8]Tính $HK=?cm$

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=> I là trung điểm BC
=> $BI=CI=2cm$
Ta có: $\Delta AIC \sim \Delta BHC$
=> $\dfrac{AC}{BC}=\dfrac{IC}{HC}$
<=> $HC=\dfrac{4.2}{8}=1 (cm)$
=> $AH=7cm$
=> $\dfrac{HK}{BC}=\dfrac{AH}{AC}$
<=> $HK=\dfrac{4.7}{8}=3,5 (cm)$
 
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