[Toán 8]tìm x

C

chaugiang81


b$.(x-1)(x+2) - (x+1)x$
$= x^2 +x -2 - x^2 -x $
$= -2 $
a. $x(x-1)- (x+1)^2 =4$
$<=> x^2 -x -x^2 -2x -1 =4$
$<=> -3x -1 = 4 $
$=> x = \dfrac{-5}{3}$
 
Last edited by a moderator:
Top Bottom