[Toán 8] Tìm x,y,z

P

phamhuy20011801

PT $\leftrightarrow xyz-(xy+yz+xz)+x+y+z-1=0\\
\leftrightarrow yz(x-1)-y(x-1)-z(x-1)+(x-1)=0\\
\leftrightarrow (yz-y-z+1)(x-1)=0\\
\leftrightarrow (x-1)(y-1)(z-1)=0$

$\leftrightarrow x=1$ hoặc $y=1$ hoặc $z=1$
 
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