[Toán 8] Tìm x,y biết:

N

nguyenbahiep1

câu a

[TEX](2x+2y)^2 + (x-1)^2 + (y+1)^2 \geq 0 \Rightarrow 2x = - 2y \\ x = 1 \\ y = - 1 [/TEX]

câu b

[TEX](x-y)^2 + (2y+1)^2 \geq 0 \Rightarrow x = y \\ y = -\frac{1}{2} = x[/TEX]

câu c

[TEX](x-1)^2 + (2y+2)^2 + (z-3)^2 +1 > 0 \forall x, y, z[/TEX]
 
Last edited by a moderator:
You must log in or register to reply here.
Top Bottom