[TOÁN 8] tìm số dư cần gấp

I

iceghost

$(x+2)(x+4)(x+6)(x+8)+2009 \\
=(x+2)(x+8)(x+4)(x+6)+2009 \\
=(x^2+10x+16)(x^2+10x+24)+2009 \\
=(x^2+10x+16)(x^2+10x+16+8)+2009 \\
=(x^2+10x+16)^2+8(x^2+10x+16)+2009 \quad chia \quad x^2+10x+16 \; \text{dư} \;2009$
 
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