[Toán 8] Phương trình nghiệm nguyên

A

angleofdarkness

Pt \Leftrightarrow $8(2 - x) +x^2+ y^2 = z^2 +x^2$

\Leftrightarrow $(x-4)^2+y^2=x^2+z^2$

Xét các T.h $\begin{bmatrix}
\left\{\begin{matrix}
(x-4)^2=x^2 & \\
y^2=z^2 &
\end{matrix}\right. & & \\
\left\{\begin{matrix}
(x-4)^2=z^2 & \\
y^2=x^2 &
\end{matrix}\right. & &
\end{bmatrix}$

P/S: Chịu khó xét =)) =))
 
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