[Toán 8] Phân tích đa thức thành nhân tử

T

thaolovely1412

[TEX]x^4 + 2013x^2 + 2012x + 2013[/TEX]
[TEX]=(x^4+x^2+1)+(2012x^2+2012x+2012)[/TEX]
[TEX]=(x^2+x+1)(x^2-x+1)+2012(x^2+x+1)[/TEX]
[TEX]=(x^2+x+1)(x^2-x+2013)[/TEX]
 
V

vipboycodon

$x^4 + 2013x^2 + 2012x + 2013$
= $x^4-x+2013x^2+2013x+2013$
= $x(x^3-1)+2013(x^2+x+1)$
= $x(x-1)(x^2+x+1)+2013(x^2+x+1)$
= $(x^2+x+1)(x^2-x+2013)$
 
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