[Toán 8]Phân thức đại số

L

lamdetien36

$\dfrac{3x^3-2x^2+4x-5}{6x^2+3x-9}$
$=\dfrac{3x^3 - 3x^2 + x^2 - x + 5x - 5}{6x^2 - 6x + 9x - 9}$
$=\dfrac{3x^2(x - 1) + x(x - 1) + 5(x - 1)}{6x(x - 1) + 9(x - 1)}$
$=\dfrac{(3x^2 + x + 5)(x - 1)}{(6x + 9)(x - 1)}$
$=\dfrac{3x^3 + x + 5}{6x + 9}$
 
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