[Toán 8] nâng cao

H

hieu09062002

Last edited by a moderator:
P

phamhuy20011801

:|
Bài 2:
Đặt $x^2-2x=a$
$x^2-16=b$
Ta có: $a^3-b^3+(b-a)^3=0\\
\iff a^3-b^3+b^3-3ab(b-a)-a^3=0\\
\iff 3ab(b-a)=0\\
\iff 3(x^2-2x)(x^2-16)(2x-16)=0\\
\iff 6x(x-2)(x+4)(x-4)(x-8)=0$
...
 
Top Bottom