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long09455
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1. Cho tam giác ABC nhọn, có 3 đường cao AD, BM, CN. Gọi H là trực tâm của tam giác ABC.
CM: [TEX]\frac{HD}{AD}+\frac{HM}{BM}+\frac{HN}{CN}[/TEX]=[TEX]\frac{BD}{BC}.\frac{MC}{MA}.\frac{NA}{NB}[/TEX]
CM: [TEX]\frac{HD}{AD}+\frac{HM}{BM}+\frac{HN}{CN}[/TEX]=[TEX]\frac{BD}{BC}.\frac{MC}{MA}.\frac{NA}{NB}[/TEX]
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