[Toán 8] Giúp với

N

niemkieuloveahbu

[TEX]BDT \Leftrightarrow \frac{1}{2}(a-b)^2+\frac{1}{2}(b-c)^2+\frac{1}{2}(c-a)^2 \geq 0( luon\ dung)[/TEX]
 
S

songoku1998

cach giai

ta có 1/2a^2-ab+1/2b^2+1/2b^2-bc+1/2c^2+1/2c^2-ac+1/2a^2\geq0(tự cm)
\Leftrightarrowa^2+b^2+c^2\geqab+bc+ac
 
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