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heorungcodon0987


1 ) a) ( x+2).(x-2) = x.(x-4)
b) $x^3$ - $x^2$ + 4x - 4 =0
C ) $\frac{x-2}{x-1}$-$\frac{3}{x+1}$=$\frac{-3}{x^2-1}$
Chú ý tiêu đề.
b) $x^3$ - $x^2$ + 4x - 4 =0
C ) $\frac{x-2}{x-1}$-$\frac{3}{x+1}$=$\frac{-3}{x^2-1}$
Chú ý tiêu đề.
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