[Toán 8] Dạng tìm Min

L

lp_qt

$A= x^2+2y^2+2xy-6x-4y+13$

$=(x^2+y^2+9+2xy-6x-6y) + (y^2+2y+1)+3$

$=(x+y-3)^2+(y-1)^2+3 \ge 3$

dấu = xảy ra \Leftrightarrow $y=-1;x=4$
 
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