[Toán 8] Chứng Minh

T

tram8A1

a. X^2-5*X+10=x^2-2*5/2*x+(5/2)^2
=(x-5/2)^2+15/4
do (x-5/2)^2>=0 nen (x-5/2)^2+15/4 >=15/4 voi moi x
b. 2xX^2+3xX+8=2*(x^2+3/2*x+4)
=2*(x^2+2*3/4*x+(3/4)^2+55/16)
=2*(x^2+2*3/4*x+(3/4)^2)+55/8
do 2*(x^2+2*3/4*x+(3/4)^2>=0 nen 2*(x^2+2*3/4*x+(3/4)^2)+55/8>=55/8 voi moi x
 
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I

iceghost

Đề hình như bạn viết dư 1 chữ x
$a)a)x^2-5x+10=x^2+2.\dfrac52x+\dfrac{25}4+\dfrac{15}4=(x-\dfrac52)^2+\dfrac{15}4 \ge \dfrac{15}4 > 0$
 
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