[Toán 8] Chứng minh

L

legendyugi

[TEX]\frac{a}{ab+a+1} +\frac{b}{bc+b+1} +\frac{c}{ac+c+1} =\frac{a}{ab+a+abc} +\frac{b}{bc+b+1} +\frac{abc^2}{ac+abc^2+abc}=\frac{1}{b+1+bc}+\frac{b}{bc+b+1}+\frac{bc}{1+bc+b}=1 \Rightarrow DPCM[/TEX]/:)
 
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