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tìm số dư khi chia 1992^1993+1994^1995 cho 7
Ta thấy $1995 \vdots 7$, do đó:
$1992^{1993}+1994^{1995}=(BS 7-3)^{1993}+(BS 7-1)^{1995}=BS 7-3^{1993}+BS 7-1$
Mặt khác ta có: $3^{1993}=3^{6k+1}=3.(3^3)^{2k}=3.(BS 7-1)^{2k}=3.(BS 7 + 1) = BS 7 + 1$, nên:
$1992^{1993}+1994^{1995}=BS 7 -(BS 7 - 3) - 1=BS 7 -4 $ chia cho 7 dư 3
Vậy ....