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I

iceghost

$\dfrac{a+b}{a-b}=\dfrac{c+d}{c-d} \\
\iff (a+b)(c-d)=(a-b)(c+d) \\
\iff ac-ad+bc-bd=ac+ad-bc-bd \\
\iff ac-ad+bc-bd-ac-ad+bc+bd=0 \\
\iff -2ad+2bc=0 \\
\iff 2ad = 2bc \\
\iff ad = bc \\
\iff \dfrac{a}{b}=\dfrac{c}{d} \\
\iff x=y$
 
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B

baobadao2512

Cách khác

$\dfrac{a+b}{a-b}=\dfrac{c+d}{c-d}$
\Rightarrow $\dfrac{a+b}{c+d}= \dfrac{a-b}{c-d}= \dfrac{a}{c}=\dfrac{b}{d}$
\Rightarrow$\dfrac{a}{b}= \dfrac{c}{d}$
\Rightarrow $x=y$

p/s: đây là bài trong vio phải ko bn
 
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