[Toán 7] Tìm GTNN, GTLN

A

anh5anqb1

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B

baochauhn1999

$x^2+x+1=x^2+x+\frac{1}{4}+\frac{3}{4}=(x+\frac{1}{2})^2+\frac{3}{4}$\geq$\frac{3}{4}$
$"=" <=>x=\frac{-1}{2}$
 
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