[Toán 7] Tỉ lệ thức

T

thaongoccute

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T

thanhcong1594

b .
latex.php


latex.php


latex.php


latex.php


latex.php


latex.php

GG
 
P

phamhuy20011801

a,
$\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+1+3y-2}{5+7}=\dfrac{2x+3y-1}{12}$

Mặt khác $\dfrac{2x+1}{5}=\dfrac{2y-2}{7}=\dfrac{2x+3y-1}{6x}$

$\rightarrow \dfrac{2x+3y-1}{12}=\dfrac{2x+3y-1}{6x}$
$\rightarrow 6x=12$

Suy ra $x=2$
 
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