[Toán 7] Giai thừa

N

nhung6b5a1

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P

phamvananh9

[TEX][/TEX]
= $\frac{2-1}{2!} + \frac{3-1}{3!} + \frac{4-1}{4!} +.........+\frac{100-1}{100!}$
=$ 1 - \frac{1}{2!} + \frac{1}{2!} - \frac{1}{3!} + \frac{1}{3!}- \frac{1}{4!}+.......+ \frac{1}{99!} - \frac{1}{100!}$
= 1- $\frac{1}{100!}$ < 1.
 
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