[Toán 7] Đề thi HSG

V

vodka00

vì $x=2012 => 2013=x+1$
$=>P(x)= x^5-(x+1)(x^4)+(x+1)(x^3)-(x+1)(x^2)+x(x+1)-x-2$
$=>P(x)= x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2-x-2$
$=>P(x)= -x-2=-2012-2=-2014$
:)>-
 
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