toán 7 chứng minh đây.

H

harrypham

a, [TEX]7^4+7^5+7^6=7^4(1+7+7^2)=7^4 \cdot 55[/TEX] chia hết cho 55.
b, [TEX]16^5+2^{15}= (2^4)^5+2^{15}= 2^{20}+2^{15}=2^{15}(1+2^5)=33 \cdot 2^{15}[/TEX] chia hết cho 33.
c, [TEX]81^7-27^9-9^{13}=(3^4)^7-(3^3)^9-(3^2)^{13}[/TEX]
[TEX]= 3^{28}-3^{27}-3^{26}=3^{26}(9-3-1)=3^{26} \cdot 7[/TEX] không chia hết cho [TEX]40^5[/TEX].
 
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