[tex]A=\frac{1}{2.8+1}+\frac{1}{2.9+1}+\frac{1}{2.10+1}+...+\frac{1}{2.19+1}\\\\ > \frac{1}{2.8+2}+\frac{1}{2.9+2}+...+\frac{1}{2.19+2}=B\\\\ => B=\frac{1}{2.9}+\frac{1}{2.10}+...+\frac{1}{2.20}\\\\ =\frac{1}{2}.(\frac{1}{9}+\frac{1}{10}+...+\frac{1}{20})\\\\ >\frac{1}{2}.(\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20})=\frac{1}{2}.\frac{12}{20}=0,3\\\\ => A>B>0,3[/tex]