[Toán 6] Tính

B

braga

[TEX]A=1.2+2.3+3.4+...+99.100 [/TEX]

[TEX]3A=1.2.3+2.3.3+3.4.3+...+99.100.3[/TEX]

[TEX]3A=1.2.3+2.3(4-1)+3.4.(5-2)+........+99.100.(101-1)[/TEX]

[TEX]3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+.............+99.100.101-97.98.100[/TEX]

[TEX]3A=99.100.101 \Rightarrow A=\frac{99.100.101}{3}=333300[/TEX]

Tổng quát: [TEX]\fbox{1.2+2.3+3.4+...+n(n+1)=\frac{n(n+1)(n+2)}{3}[/TEX]

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