[Toán 6]Tính giá trị biểu thức

H

hoanganh1999

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H

harrypham

cho [TEX]A=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+......+\frac{1}{308}+\frac{1}{309}[/TEX]


[TEX]B=\frac{308}{1}+\frac{307}{2}+\frac{306}{3}+......+\frac{3}{306}+\frac{2}{307}+\frac{1}{308}[/TEX]

Tính A: B

Ta phân tích
[TEX]B= \frac{309-1}{1}+ \frac{309-2}{2} + \frac{309-3}{3}+...+ \frac{309-308}{308}= 309( \frac{1}{2}+ \frac{1}{3} +...+ \frac{1}{308})+309-308[/TEX]
[TEX]B=309( \frac{1}{2}+ \frac{1}{3} +...+ \frac{1}{308})+1= 309( \frac{1}{2}+ \frac{1}{3} +...+ \frac{1}{308})+ \frac{309}{309} = 309( \frac{1}{2}+ \frac{1}{3} +...+ \frac{1}{308}+ \frac{1}{309}) [/TEX]

Như vậy [TEX]\frac{A}{B}= \frac{1}{309}[/TEX]
 
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