[Toán 6] Tìm x

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longmeo_6b

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nguyenbahiep1

b) (x - 7).(x+1)
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c) (x^2 - 12).(x^2 - 6)
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câu b

[laTEX]-1 \leq x \leq 7[/laTEX]


câu c

[laTEX]6 \leq x^2 \leq 12 \Rightarrow - 2\sqrt{3} \leq x \leq 2\sqrt{3} \\ \\ x \geq \sqrt{6} , x \leq - \sqrt{6}[/laTEX]
 
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